Skip to content

Graduate · Real Analysis

Sequences & series of functions

80 problems in this skill, each with a solver-verified answer key. Answers are checked the moment you submit — with a hint if you want one and a worked solution afterwards.

What the problems look like

A few statements from this skill. Answers, hints and worked solutions live in the practice session.

  1. Warm-up

    Consider the series ∑n=1∞23nsin⁡(nx)\sum_{n=1}^{\infty} \dfrac{2}{3^{n}}\sin(nx) on R\mathbb{R}. The Weierstrass M−M^-test applies with Mn=23nM_n = \dfrac{2}{3^{n}}, since ∣sin⁡(nx)∣≤1|\sin(nx)| \le 1 for every xx. Compute ∑n=1∞Mn\sum_{n=1}^{\infty} M_n (the M−M^-test bound certifying uniform convergence).

  2. Warm-up

    Consider the series ∑n=1∞35nsin⁡(nx)\sum_{n=1}^{\infty} \dfrac{3}{5^{n}}\sin(nx) on R\mathbb{R}. The Weierstrass M−M^-test applies with Mn=35nM_n = \dfrac{3}{5^{n}}, since ∣sin⁡(nx)∣≤1|\sin(nx)| \le 1 for every xx. Compute ∑n=1∞Mn\sum_{n=1}^{\infty} M_n (the M−M^-test bound certifying uniform convergence).

  3. Warm-up

    Consider the series ∑n=1∞62nsin⁡(nx)\sum_{n=1}^{\infty} \dfrac{6}{2^{n}}\sin(nx) on R\mathbb{R}. The Weierstrass M−M^-test applies with Mn=62nM_n = \dfrac{6}{2^{n}}, since ∣sin⁡(nx)∣≤1|\sin(nx)| \le 1 for every xx. Compute ∑n=1∞Mn\sum_{n=1}^{\infty} M_n (the M−M^-test bound certifying uniform convergence).

Problems shown under their original terms: Generated (template, solver-computed).

Practice this free, right now

Unlimited math practice is on the free plan — no card, no trial clock.

See every Real Analysis skill for graduate