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College+ · Numerical Methods

Newton's method

92 problems in this skill, each with a solver-verified answer key. Answers are checked the moment you submit — with a hint if you want one and a worked solution afterwards.

What the problems look like

A few statements from this skill. Answers, hints and worked solutions live in the practice session.

  1. Warm-up

    Newton's method applied to f(x)=1x−3f(x) = \dfrac{1}{x} - 3 gives the division-free iteration xn+1=xn(2−3xn)x_{n+1} = x_n(2 - 3x_n) for computing 1/31/3. Starting from x0=1/2x_0 = 1/2, find (i) the next iterate x1x_1 and (ii) its error term e1=1−3x1e_1 = 1 - 3x_1. (The errors en=1−3xne_n = 1 - 3x_n satisfy en+1=en2e_{n+1} = e_n^{2}.)

  2. Warm-up

    Newton's method applied to f(x)=1x−6f(x) = \dfrac{1}{x} - 6 gives the division-free iteration xn+1=xn(2−6xn)x_{n+1} = x_n(2 - 6x_n) for computing 1/61/6. Starting from x0=1/4x_0 = 1/4, find (i) the next iterate x1x_1 and (ii) its error term e1=1−6x1e_1 = 1 - 6x_1. (The errors en=1−6xne_n = 1 - 6x_n satisfy en+1=en2e_{n+1} = e_n^{2}.)

  3. Warm-up

    Newton's method applied to f(x)=1x−2f(x) = \dfrac{1}{x} - 2 gives the division-free iteration xn+1=xn(2−2xn)x_{n+1} = x_n(2 - 2x_n) for computing 1/21/2. Starting from x0=1/5x_0 = 1/5, find (i) the next iterate x1x_1 and (ii) its error term e1=1−2x1e_1 = 1 - 2x_1. (The errors en=1−2xne_n = 1 - 2x_n satisfy en+1=en2e_{n+1} = e_n^{2}.)

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