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College+ · Linear Algebra II

Orthogonal matrices

254 problems in this skill, each with a solver-verified answer key. Answers are checked the moment you submit — with a hint if you want one and a worked solution afterwards.

What the problems look like

A few statements from this skill. Answers, hints and worked solutions live in the practice session.

  1. Warm-up

    Let a=5a = 5, b=12b = 12, and c=13c = 13, so a2+b2=c2a^{2}+b^{2}=c^{2}, and let R=(5/13−12/1312/135/13)R = \begin{pmatrix} 5/13 & -12/13 \\ 12/13 & 5/13 \end{pmatrix}. RR is orthogonal, so R−1=RTR^{-1} = R^{T}. Find the row 22, column 11 entry of R−1R^{-1}.

  2. Warm-up

    Let a=21a = 21, b=20b = 20, and c=29c = 29, so a2+b2=c2a^{2}+b^{2}=c^{2}, and let R=(21/29−20/2920/2921/29)R = \begin{pmatrix} 21/29 & -20/29 \\ 20/29 & 21/29 \end{pmatrix}. RR is orthogonal, so R−1=RTR^{-1} = R^{T}. Find the row 22, column 11 entry of R−1R^{-1}.

  3. Warm-up

    Let a=3a = 3, b=4b = 4, and c=5c = 5, so a2+b2=c2a^{2}+b^{2}=c^{2}, and let R=(3/5−4/54/53/5)R = \begin{pmatrix} 3/5 & -4/5 \\ 4/5 & 3/5 \end{pmatrix}. RR is orthogonal, so R−1=RTR^{-1} = R^{T}. Find the row 22, column 11 entry of R−1R^{-1}.

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