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Grade 12 · Precalculus

Law of sines & cosines

120 problems in this skill, each with a solver-verified answer key. Answers are checked the moment you submit — with a hint if you want one and a worked solution afterwards.

What the problems look like

A few statements from this skill. Answers, hints and worked solutions live in the practice session.

  1. Warm-up

    In triangle ABCABC, a=12a = 12, b=20b = 20, and the included angle C=120∘C = 120^{\circ}, so cos⁡C=−12\cos C = -\frac{1}{2}. Use the law of cosines to find the third side cc.

  2. Warm-up

    In triangle ABCABC, a=9a = 9, b=15b = 15, and the included angle C=120∘C = 120^{\circ}, so cos⁡C=−12\cos C = -\frac{1}{2}. Use the law of cosines to find the third side cc.

  3. Warm-up

    In triangle ABCABC, a=18a = 18, b=30b = 30, and the included angle C=120∘C = 120^{\circ}, so cos⁡C=−12\cos C = -\frac{1}{2}. Use the law of cosines to find the third side cc.

Problems shown under their original terms: Generated (template, solver-computed).

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See every Precalculus skill for grade 12